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(D) According to Pascal's Law,the pressure applied to an enclosed fluid is transmitted undiminished to every portion of the fluid and the walls of the

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(D) According to Pascal's Law,the pressure applied to an enclosed fluid is transmitted undiminished to every portion of the fluid and the walls of the containing vessel.For a hydraulic lift,the pressure on both pistons is equal: $P_1 = P_2$.This implies $\frac{F_1}{A_1} = \frac{F_2}{A_2}$,where $F_1$ is the force on the smaller piston,$A_1$ is its area,$F_2$ is the force (weight) on the larger piston,and $A_2$ is its area.The area of a circular piston is given by $A = \pi r^2$.Thus,$\frac{F_1}{\pi r_1^2} = \frac{F_2}{\pi r_2^2}$,which simplifies to $F_2 = F_1 	imes (\frac{r_2}{r_1})^2$.Given $F_1 = 250 \ N$,$r_1 = 5 \ cm$,and $r_2 = 50 \ cm$.Substituting the values: $F_2 = 250 	imes (\frac{50}{5})^2 = 250 	imes (10)^2 = 250 	imes 100 = 25,000 \ N$.Converting to kiloNewtons: $F_2 = 25 \ kN$.

In a hydraulic lift,if the radius of the smaller piston is $5 \ cm$,and the radius of the larger piston is $50 \ cm$,then the weight that the larger piston can support when a force of $250 \ N$ is applied to the smaller piston is (in $kN$)

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