In a population,the frequency of the M allele | vedclass

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(B) According to the Hardy-Weinberg principle,$p + q = 1$,where $p$ is the frequency of the dominant allele and $q$ is the frequency of the recessive

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$4$

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(B) According to the Hardy-Weinberg principle,$p + q = 1$,where $p$ is the frequency of the dominant allele and $q$ is the frequency of the recessive allele.Given that the frequency of the $M$ allele $(p)$ is $0.8$,we can calculate the frequency of the recessive allele $(q)$ as:$q = 1 - p = 1 - 0.8 = 0.2$.The frequency of the homozygous recessive genotype is represented by $q^2$.Therefore,$q^2 = (0.2)^2 = 0.04$.Converting this to a percentage: $0.04 	imes 100 = 4\%$.Thus,the correct option is $B$.

In a population,the frequency of the $M$ allele is $0.8$. Calculate the frequency of the homozygous recessive genotype in that population. (in $\%$)

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