In a resonance pipe, the first and second resonances are obtained at depths $22.7 \,cm$ and $70.2 \,cm$ respectively. What will be the end correction (in $\,cm$)?

  • A
    $1.05$
  • B
    $115.5$
  • C
    $92.5$
  • D
    $113.5$

Explore More

Similar Questions

The number of possible natural oscillations of an air column in a pipe closed at one end of length $85 \, cm$ whose frequencies lie below $1250 \, Hz$ are (Velocity of sound $= 340 \, m s^{-1}$)

In a resonance column,first and second resonances are obtained at depths $22.7 \, cm$ and $70.2 \, cm$. The third resonance will be obtained at a depth (in $cm$):

If a pipe gives notes of frequencies $375 \ Hz$,$625 \ Hz$,and $875 \ Hz$,what is the fundamental frequency of the pipe and its type?

If the length of a closed organ pipe is $1 \ m$ and the velocity of sound is $330 \ m/s$,then the frequency for the second note (first overtone) is:

When an open pipe is closed from one end, the second overtone of the closed pipe is higher in frequency by $100 \text{ Hz}$ than the first overtone of the open pipe. The fundamental frequency of the open pipe will be (Neglect end correction). (in $\text{ Hz}$)

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo