In a single throw of 2 dice, what is the prob | vedclass

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(A) 'doublet' means that both the dice show the same number on the uppermost faces.When $2$ dice are thrown, the total number of possible outcomes is

Vedclass · Accepted Answer

$\frac{1}{6}$

Vedclass · Answer

(A) 'doublet' means that both the dice show the same number on the uppermost faces.When $2$ dice are thrown, the total number of possible outcomes is $6 	imes 6 = 36$.The outcomes favourable to the event of getting a doublet are:$(1,1), (2,2), (3,3), (4,4), (5,5), (6,6)$Thus, the number of favourable cases $= 6$.Therefore, the probability of getting a doublet is:$P(	ext{doublet}) = \frac{	ext{Number of favourable cases}}{	ext{Total number of possible outcomes}} = \frac{6}{36} = \frac{1}{6}$.

In a single throw of $2$ dice, what is the probability of a doublet?

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