In a solution of pH = 5,more acid is added in | vedclass

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(B) The initial hydrogen ion concentration is $[H^{+}]_1 = 10^{-pH_1} = 10^{-5} \ M$. The final hydrogen ion concentration is $[H^{+}]_2 = 10^{-pH_2}

Vedclass · Accepted Answer

$1000$

Vedclass · Answer

(B) The initial hydrogen ion concentration is $[H^{+}]_1 = 10^{-pH_1} = 10^{-5} \ M$. The final hydrogen ion concentration is $[H^{+}]_2 = 10^{-pH_2} = 10^{-2} \ M$. The increase in hydrogen ion concentration is the ratio of the final concentration to the initial concentration: $	ext{Increase} = \frac{[H^{+}]_2}{[H^{+}]_1} = \frac{10^{-2}}{10^{-5}} = 10^{(-2 - (-5))} = 10^3 = 1000 \ 	ext{times}$.

In a solution of $pH = 5$,more acid is added in order to reduce the $pH$ to $2$. The increase in hydrogen ion concentration is $......$ times.

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