In a switching circuit, if the combination (S | vedclass

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(C) Let $1$ represent the $ON$ state and $0$ represent the $OFF$ state.The circuit is represented by the Boolean expression: $L = (S_1 \land S_2) \lor

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$S_1$ and $S_2$ both $ON$ or $S_1$ and $S_2$ both $OFF$

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(C) Let $1$ represent the $ON$ state and $0$ represent the $OFF$ state.The circuit is represented by the Boolean expression: $L = (S_1 \land S_2) \lor (S'_1 \land S'_2)$.Here, $S'_1$ is the negation of $S_1$ (i.e., $S'_1 = 
eg S_1$) and $S'_2$ is the negation of $S_2$ (i.e., $S'_2 = 
eg S_2$).The circuit is lit $(L=1)$ if $(S_1 \land S_2) = 1$ or $(S'_1 \land S'_2) = 1$.$(S_1 \land S_2) = 1$ implies $S_1 = 1$ and $S_2 = 1$.$(S'_1 \land S'_2) = 1$ implies $S'_1 = 1$ and $S'_2 = 1$, which means $S_1 = 0$ and $S_2 = 0$.Thus, the room is lit when $S_1$ and $S_2$ are both $ON$ or both $OFF$.

In a switching circuit, if the combination $(S_1 \land S_2)$ is connected in parallel to the combination $(S'_1 \land S'_2)$, then the room is lit only when ...

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