In a transistor,a change of 8.0, mA in the em | vedclass

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(D) For a transistor,the relationship between the changes in currents is given by the equation: $\Delta I_e = \Delta I_c + \Delta I_b$. Given: $\Delta

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$200$

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(D) For a transistor,the relationship between the changes in currents is given by the equation: $\Delta I_e = \Delta I_c + \Delta I_b$. Given: $\Delta I_e = 8.0\, mA$ and $\Delta I_c = 7.8\, mA$. Substituting these values into the equation: $8.0\, mA = 7.8\, mA + \Delta I_b$. Solving for the change in base current: $\Delta I_b = 8.0\, mA - 7.8\, mA = 0.2\, mA$. Converting the result to microamperes $(\mu A)$: $0.2\, mA = 0.2 	imes 10^3\, \mu A = 200\, \mu A$.

In a transistor,a change of $8.0\, mA$ in the emitter current produces a change of $7.8\, mA$ in the collector current. What change in the base current is necessary to produce the same change in the collector current? (in $\mu A$)

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