In a transistor (beta=50),the voltage across | vedclass

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(A) Given: Current gain $\beta = 50$,Load resistance $R_C = 5 \, k\Omega = 5000 \, \Omega$,Voltage across load $V_C = 5 \, V$.First,calculate the coll

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$0.02$

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(A) Given: Current gain $\beta = 50$,Load resistance $R_C = 5 \, k\Omega = 5000 \, \Omega$,Voltage across load $V_C = 5 \, V$.First,calculate the collector current $I_C$ using Ohm's law:$I_C = \frac{V_C}{R_C} = \frac{5 \, V}{5000 \, \Omega} = 1 	imes 10^{-3} \, A = 1 \, mA$.Now,use the relation for current gain $\beta$ to find the base current $I_B$:$\beta = \frac{I_C}{I_B} \implies I_B = \frac{I_C}{\beta}$.Substituting the values:$I_B = \frac{1 \, mA}{50} = 0.02 \, mA$.Therefore,the base current is $0.02 \, mA$.

In a transistor $(\beta=50)$,the voltage across $5 \, k\Omega$ load resistance in the collector circuit is $5 \, V$. The base current is ......... $mA$.

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