In a transistor circuit,the collector current is changed by $8.9 \ mA$,if the emitter current is changed by $9.0 \ mA$. The value of current amplification factor,$\beta$ is

For a transistor in $CE$ mode to be used as an amplifier,it must be operated in:

In a $CE$ circuit,the collector of a transistor is kept at a constant voltage $V_C = 1.5 \ V$. When the base current changes from $100 \ \mu A$ to $150 \ \mu A$,the collector current changes from $5 \ mA$ to $10 \ mA$. The current gain $\beta$ for this transistor is:

The given transistor amplifier connection is

$A$ transistor has a current amplification factor of $60$. In a $CE$ amplifier, input resistance is $1 \, k\Omega$ and output voltage is $0.01 \, V$. The transconductance is (in $SI$ units)

In the following common emitter configuration, an $NPN$ transistor with current gain $\beta = 100$ is used. The output voltage of the amplifier will be