In a transistor in $CE$ configuration,the ratio of power gain to voltage gain is

In a $p-n-p$ transistor,

An $npn$ transistor operates as a common emitter amplifier with a power gain of $10^{6}$. The input circuit resistance is $100\, \Omega$ and the output load resistance is $10\, k\Omega$. The common emitter current gain $\beta$ will be (Round off to the nearest integer).

In a transistor (common emitter configuration) the ratio of power gain to voltage gain is ($\alpha$ and $\beta$ are current ratios)

The correct relation between $\alpha$ (ratio of collector current to emitter current) and $\beta$ (ratio of collector current to base current) of a transistor is :

In a common emitter amplifier,the current gain is $62$. The collector resistance and input resistance are $5\,k\Omega$ and $500\,\Omega$ respectively. If the input voltage is $0.01\,V$,the output voltage is $..........\,V$.