In a triangle $ABC$ with usual notations,if $b \sin C(b \cos C + c \cos B) = 42$,then the area of triangle $ABC$ is:

  • A
    $42 \text{ sq.units}$
  • B
    $21 \text{ sq.units}$
  • C
    $24 \text{ sq.units}$
  • D
    $12 \text{ sq.units}$

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