In a triangle $ABC$, if $a=7, c=11, \cos A=\frac{17}{22}, \cos C=\frac{1}{14}$, then $b \tan \frac{B}{2} \tan \frac{C-A}{2} =$

  • A
    $18$
  • B
    $14$
  • C
    $2$
  • D
    $9$

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