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(B) The fringe width $\beta$ in a Young's double slit experiment is given by the formula: $\beta = \frac{D \lambda}{d}$.Here,$D = 1.5 \; m$ is the dis

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(B) The fringe width $\beta$ in a Young's double slit experiment is given by the formula: $\beta = \frac{D \lambda}{d}$.Here,$D = 1.5 \; m$ is the distance between the slits and the screen.$\lambda = 589 \; nm = 589 	imes 10^{-9} \; m$ is the wavelength of the light source.$d = 0.15 \; mm = 0.15 	imes 10^{-3} \; m$ is the separation between the slits.Substituting these values into the formula:$\beta = \frac{1.5 	imes 589 	imes 10^{-9}}{0.15 	imes 10^{-3}}$$\beta = \frac{1.5}{0.15} 	imes 589 	imes 10^{-6} \; m$$\beta = 10 	imes 589 	imes 10^{-6} \; m = 5890 	imes 10^{-6} \; m = 5.89 	imes 10^{-3} \; m$.Rounding to one decimal place,$\beta \approx 5.9 	imes 10^{-3} \; m = 5.9 \; mm$.

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