In an $L-C-R$ series $AC$ circuit,$L = 9 \ H$,$R = 10 \ \Omega$,and $C = 100 \ \mu F$. The $Q$-factor of the circuit is . . . . . . .

At resonance frequency,the impedance in a series $LCR$ circuit is

$L, C, R$ represent physical quantities inductance,capacitance,and resistance respectively. The combinations which have the dimensions of frequency are

If the frequency of the $AC$ supply is equal to the resonant frequency,which ammeter will show zero reading?

In a series resonant $R-L-C$ circuit, the voltage across $R$ is $100 \, V$ and the value of $R = 1000 \, \Omega$. The capacitance of the capacitor is $2 \times 10^{-6} \, F$; the angular frequency of the $AC$ source is $200 \, rad \, s^{-1}$. Then the potential difference across the inductance coil is: (in $V$)

In an $LCR$ circuit,$L = 8.0 \, H$,$C = 0.5 \, \mu F$,and $R = 100 \, \Omega$ are connected in series. The resonance angular frequency is ........ $rad/s$.