In an $AC$ circuit,$V$ and $I$ are given below. Find the power dissipated in the circuit:
$V = 50 \sin(50t) \ V$
$I = 50 \sin(50t + \frac{\pi}{3}) \ mA$ (in $W$)

The power dissipated in a resistor of resistance $R$ when an alternating current with a peak value of $I_p$ flows through it is:

$A$ $LCR$ series circuit driven with $V_{rms} = 90 \text{ V}$ at frequency $f_d = 30 \text{ Hz}$ has resistance $R = 80 \text{ }\Omega$, an inductance with inductive reactance $X_L = 20.0 \text{ }\Omega$ and capacitance with capacitive reactance $X_C = 80.0 \text{ }\Omega$. The power factor of the circuit is . . . . . . .

In an $A.C.$ circuit,$V$ and $I$ are given by:
$V = 100 \sin(100 t) \text{ V}$
$I = 100 \sin(100 t + \pi/3) \text{ mA}$
The power dissipated in the circuit is:

In a series $LCR$ circuit,$R = 18 \ \Omega$ and the impedance $Z = 30 \ \Omega$. An $rms$ voltage of $210 \ V$ is applied across the circuit. The true power consumed in the $AC$ circuit is nearly: (in $W$)

$A$ sinusoidal $AC$ current flows through a resistor of resistance $R$. If the peak current is $I_p$,then the power dissipated is