Class 12PhysicsElectric Potential and CapacitanceCharging and Discharging of Capacitance and RC circuit (DC)
MediumIn an $RC$ circuit as shown below,both switches are open initially. Now switch $S_1$ is closed and $S_2$ is kept open. ($q$ is the charge on the capacitor and $\tau = RC$ is the capacitive time constant). Which of the following statements is correct?
- AAt $t = \frac{\tau}{2}$,$q = CV(1 - e^{-0.5})$
- BWork done by the battery is half of the energy dissipated in the resistor
- CAt $t = \tau$,$q = \frac{CV}{2}$
- DAt $t = 2\tau$,$q = CV(1 - e^{-2})$
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$A$ charged capacitor is allowed to discharge through a resistor by closing the key at the instant $t = 0$. At the instant $t = (\ln 4) \, \mu s$,the reading of the ammeter falls to half the initial value. The resistance of the ammeter is equal to
After the switch shown in Figure $A$ is closed,there is a current $i$ through the resistance $R$. Figure $B$ indicates current variation curves $a, b, c,$ and $d$ for four sets of values of $R$ and capacitance $C$:
$(i)$ $R_0$ and $C_0$
$(ii)$ $2R_0$ and $C_0$
$(iii)$ $R_0$ and $2C_0$
$(iv)$ $2R_0$ and $2C_0$
Which set goes with which curve?
$(i)$ $R_0$ and $C_0$
$(ii)$ $2R_0$ and $C_0$
$(iii)$ $R_0$ and $2C_0$
$(iv)$ $2R_0$ and $2C_0$
Which set goes with which curve?
In a $RC$ circuit, where $R$ is resistance and $C$ is capacitance, which of the following has the dimension of time?
Let $C$ be the capacitance of a capacitor discharging through a resistor $R$. Suppose $t_{1}$ is the time taken for the energy stored in the capacitor to reduce to half its initial value and $t_{2}$ is the time taken for the charge to reduce to one-fourth its initial value. Then the ratio $t_{1} / t_{2}$ will be
DifficultAIEEE 2010
View SolutionIn the circuit shown,when the key $K$ is pressed at time $t = 0$,which of the following statements about current $I$ in the resistor $AB$ is true?
Difficult
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