In an experiment,the mass of an object is mea | vedclass

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(C) Given,$F = 10.0 \pm 0.2 \, N$ and $a = 1.00 \pm 0.01 \, m/s^2$.Using Newton's second law,$F = ma$,so $m = F/a$.Calculating the mean value of mass:

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$10.0 \pm 0.3$

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(C) Given,$F = 10.0 \pm 0.2 \, N$ and $a = 1.00 \pm 0.01 \, m/s^2$.Using Newton's second law,$F = ma$,so $m = F/a$.Calculating the mean value of mass: $m = 10.0 / 1.00 = 10.0 \, kg$.For division,the relative error is given by $\frac{\Delta m}{m} = \frac{\Delta F}{F} + \frac{\Delta a}{a}$.Substituting the values: $\frac{\Delta m}{m} = \frac{0.2}{10.0} + \frac{0.01}{1.00} = 0.02 + 0.01 = 0.03$.Now,calculate the absolute error in mass: $\Delta m = 0.03 	imes m = 0.03 	imes 10.0 = 0.3 \, kg$.Therefore,the mass of the object is $m = 10.0 \pm 0.3 \, kg$.

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