In an experiment on a simple pendulum to dete | vedclass

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(B) The length of the pendulum $(L)$ is given by the sum of the length of the thread $(l)$ and the radius of the bob $(r)$.$L = l + r$Given,$l = 63.2

Vedclass · Accepted Answer

$64.3$

Vedclass · Answer

(B) The length of the pendulum $(L)$ is given by the sum of the length of the thread $(l)$ and the radius of the bob $(r)$.$L = l + r$Given,$l = 63.2 \,cm$ and diameter $d = 2.256 \,cm$.Radius $r = \frac{d}{2} = \frac{2.256}{2} = 1.128 \,cm$.$L = 63.2 + 1.128 = 64.328 \,cm$.According to the rules of significant figures in addition/subtraction,the result should be reported to the same number of decimal places as the measurement with the fewest decimal places.Here,$63.2$ has one decimal place and $1.128$ has three decimal places.Therefore,the result must be rounded to one decimal place.$L = 64.3 \,cm$.

In an experiment on a simple pendulum to determine the acceleration due to gravity,a student measures the length of the thread as $63.2 \,cm$ and the diameter of the pendulum bob as $2.256 \,cm$. The student should take the length of the pendulum to be ........... $cm$.

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