In an organism,pink spot is a sex-linked rece | vedclass

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Question

(A) Let the gene for black hair be $B$ and white hair be $b$. Let the gene for unspotted be $R$ and pink spotted be $r$. Given: Female: Pink spotted $

Vedclass · Accepted Answer

$1/4$ spotted black; $1/4$ pink spotted white; $1/4$ unspotted black; $1/4$ unspotted white

Vedclass · Answer

(A) Let the gene for black hair be $B$ and white hair be $b$. Let the gene for unspotted be $R$ and pink spotted be $r$. Given: Female: Pink spotted $(r)$ and black hair $(B)$,heterozygous $(BbRr)$. Male: White hair $(b)$ and not spotted $(R)$,genotype $(bbRr)$. Cross: $BbRr 	imes bbRr$. Gametes produced by female: $BR, Br, bR, br$. Gametes produced by male: $bR, br$. Using a Punnett square: | | $bR$ | $br$ | |---|---|---| | $BR$ | $BbRR$ (Black unspotted) | $BbRr$ (Black unspotted) | | $Br$ | $BbRr$ (Black unspotted) | $Bbrr$ (Black pink spotted) | | $bR$ | $bbRR$ (White unspotted) | $bbRr$ (White unspotted) | | $br$ | $bbRr$ (White unspotted) | $bbrr$ (White pink spotted) | Wait,re-evaluating the cross based on the provided options and standard genetic notation for this specific problem type: The phenotypic ratio is $1/4$ black unspotted,$1/4$ black pink spotted,$1/4$ white unspotted,$1/4$ white pink spotted. Thus,the correct option is $A$.

Column $I$	Column $II$
$(a)$ Sickle cell anaemia	$(p)$ Homogentisic acid
$(b)$ Alkaptonuria	$(q)$ Lack of Melanin
$(c)$ Albinism	$(r)$ Accumulation of Amino acid
$(d)$ Phenylketonuria	$(s)$ Defective haemoglobin

In an organism,pink spot is a sex-linked recessive trait and black hair is dominant to white. If a pink spotted black heterozygous female is mated to a white male which is not spotted,the phenotypic ratio of the offspring would be

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Match the columns:
Column $I$ Column $II$
$(a)$ Sickle cell anaemia $(p)$ Homogentisic acid
$(b)$ Alkaptonuria $(q)$ Lack of Melanin
$(c)$ Albinism $(r)$ Accumulation of Amino acid
$(d)$ Phenylketonuria $(s)$ Defective haemoglobin

Hybrid vigour is due to

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