In an oscillating LC circuit, the maximum cha | vedclass

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(C) The maximum energy stored in the capacitor is given by $E_{max} = \frac{Q^2}{2C}$.When the energy is stored equally between the electric and magne

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$\frac{Q}{\sqrt{2}}$

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(C) The maximum energy stored in the capacitor is given by $E_{max} = \frac{Q^2}{2C}$.When the energy is stored equally between the electric and magnetic fields, the energy in the capacitor is half of the maximum energy, i.e., $E_{cap} = \frac{1}{2} E_{max}$.Let $Q'$ be the charge on the capacitor at this instant. Then, $E_{cap} = \frac{Q'^2}{2C}$.Equating the two expressions for $E_{cap}$:$\frac{Q'^2}{2C} = \frac{1}{2} \left( \frac{Q^2}{2C} \right)$$Q'^2 = \frac{Q^2}{2}$$Q' = \frac{Q}{\sqrt{2}}$.

In an oscillating $LC$ circuit, the maximum charge on the capacitor is $Q$. When the energy is stored equally between the electric and magnetic fields, the charge on the capacitor becomes:

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