In astronomical observations,signals observed from the distant stars are generally weak. If the photon detector receives a total of $3.15 \times 10^{-18} \, J$ from the radiations of $600 \, nm$,calculate the number of photons received by the detector.

(N/A) The energy of a single photon $(E)$ is given by the formula:
$E = \frac{hc}{\lambda}$
Where:
$h = 6.626 \times 10^{-34} \, J \cdot s$ (Planck's constant)
$c = 3 \times 10^{8} \, m \cdot s^{-1}$ (Speed of light)
$\lambda = 600 \times 10^{-9} \, m$ (Wavelength)
Calculating the energy of one photon:
$E = \frac{(6.626 \times 10^{-34} \, J \cdot s)(3 \times 10^{8} \, m \cdot s^{-1})}{600 \times 10^{-9} \, m} = 3.313 \times 10^{-19} \, J$
The total number of photons $(n)$ is the total energy divided by the energy of one photon:
$n = \frac{\text{Total Energy}}{E} = \frac{3.15 \times 10^{-18} \, J}{3.313 \times 10^{-19} \, J} \approx 9.5$
Rounding to the nearest whole number,the detector receives approximately $10$ photons.