In carbon monoxide molecules,the carbon and t | vedclass

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(D) Let the mass of the carbon atom be $m_C = 12 \, u$ and the mass of the oxygen atom be $m_O = 16 \, u$.Let the distance between them be $d = 1.2 \,

Vedclass · Accepted Answer

$0.69$

Vedclass · Answer

(D) Let the mass of the carbon atom be $m_C = 12 \, u$ and the mass of the oxygen atom be $m_O = 16 \, u$.Let the distance between them be $d = 1.2 \,\mathring{A}$.Taking the carbon atom at the origin $(x_C = 0)$,the position of the oxygen atom is $x_O = 1.2 \,\mathring{A}$.The position of the centre of mass $X_{cm}$ is given by the formula:$X_{cm} = \frac{m_C x_C + m_O x_O}{m_C + m_O}$Substituting the values:$X_{cm} = \frac{12 	imes 0 + 16 	imes 1.2}{12 + 16}$$X_{cm} = \frac{19.2}{28}$$X_{cm} \approx 0.6857 \,\mathring{A} \approx 0.69 \,\mathring{A}$.Thus,the distance of the centre of mass from the carbon atom is $0.69 \,\mathring{A}$.

In carbon monoxide molecules,the carbon and the oxygen atoms are separated by a distance of $1.2 \,\mathring{A}$. The distance of the centre of mass from the carbon atom is ........ $\mathring{A}$.

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