In the case of a hydrogen atom,when an electron falls from a higher energy level to the $M$ shell,the corresponding spectral line will form a part of:
- ABalmer series
- BLyman series
- CPaschen series
- DPfund series
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Similar Questions
Calculate the ratio of the radius of the $2^{nd}$ and $3^{rd}$ orbit of a hydrogen atom. (Note: $r_n \propto n^2$)
Medium
View SolutionThe wave number of the first emission line in the Balmer series of $H$ atom spectrum is ($R =$ Rydberg constant).
The ground state energy of hydrogen atom is $-13.6 \ eV$. The energy of the second excited state of $He^{+}$ ion in $eV$ is:
Which transition in the hydrogen atomic spectrum will have the same wavelength as the transition,$n = 4$ to $n = 2$ of $He^{+}$ spectrum?
MediumAIIMS 2016
View SolutionThe energy required to excite an electron in a $H$ atom from the first orbit to the second orbit is ......
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