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(D) The species $F^{-}$,$Ne$,and $Na^{+}$ are isoelectronic,as each contains $10$ electrons with the electronic configuration $1s^2, 2s^2, 2p^6$.Since

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Nuclear charge $(Z)$

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(D) The species $F^{-}$,$Ne$,and $Na^{+}$ are isoelectronic,as each contains $10$ electrons with the electronic configuration $1s^2, 2s^2, 2p^6$.Since they have the same number of electrons,the variation in their ionic/atomic radii is determined by the nuclear charge $(Z)$.As the nuclear charge increases (from $F^{-}$ to $Ne$ to $Na^{+}$),the force of attraction between the nucleus and the electrons increases,leading to a decrease in size.

Ion	Radius $(pm)$
$Q^{a+}$	$53$
$X^{b+}$	$66$
$Y^{c+}$	$40$
$Z^{d+}$	$100$

In case of isoelectronic species,the size of $F^{-}$,$Ne$,and $Na^{+}$ is affected by:

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