In case of nitrogen,NCl_3 is possible but not | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Nitrogen $(N)$ has the electronic configuration $1s^2 2s^2 2p^3$. It lacks vacant $d$-orbitals in its valence shell,so it cannot expand its octet

Vedclass · Accepted Answer

Availability of vacant $d$-orbital in $P$ but not in $N$

Vedclass · Answer

(A) Nitrogen $(N)$ has the electronic configuration $1s^2 2s^2 2p^3$. It lacks vacant $d$-orbitals in its valence shell,so it cannot expand its octet to form $NCl_5$.Phosphorus $(P)$ has the electronic configuration $[Ne] 3s^2 3p^3 3d^0$. Due to the presence of vacant $3d$-orbitals,phosphorus can expand its octet and form $PCl_5$ by promoting an electron from the $3s$ orbital to the $3d$ orbital.Therefore,the correct reason is the availability of vacant $d$-orbitals in $P$ but not in $N$.

In case of nitrogen,$NCl_3$ is possible but not $NCl_5$,while in case of phosphorus,$PCl_3$ as well as $PCl_5$ are possible. This is due to:

Similar Questions

Which of the following elements does not react with hot concentrated sulphuric acid?

Phosphine is prepared by the reaction of

Which one of the following properties is $not$ shown by $NO$?

Ammonia is not produced in the reaction of

Vedclass Test Series

Exam Paper Generator

Online Exam Module