In the chemical scale,the relative atomic mass of the naturally occurring isotopic mixture of oxygen atoms $({}^{16}O, {}^{17}O, {}^{18}O)$ is taken as:
- A$16.002$
- B$16.000$
- C$17.000$
- D$18.000$
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$1 \ g$ of a metal nitrate produces $0.86 \ g$ of metal sulphate. The equivalent weight of the metal will be:
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View SolutionThe equivalent weight of $H_3PO_4$ in the reaction is $Ca(OH)_2 + H_3PO_4 \to CaHPO_4 + 2H_2O$
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$(Ca = 40, P = 31, O = 16)$
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View SolutionCalculate the milli-equivalents of:
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$(a) \, Ca(OH)_2$ in $74 \, g$
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