(A) Milli-equivalents (Meq.) of $Ca(OH)_2 = \frac{w}{E} \times 1000$$= \frac{74}{74 / 2} \times 1000 = 2000$$\left( \text{Since } E_{Ca(OH)_2} = \frac

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(A) Milli-equivalents (Meq.) of $Ca(OH)_2 = \frac{w}{E} \times 1000$$= \frac{74}{74 / 2} \times 1000 = 2000$$\left( \text{Since } E_{Ca(OH)_2} = \frac{74}{2} = 37 \right)$$(b)$ Meq. of $NaOH = \frac{w}{E} \times 1000$$= \frac{20}{40} \times 1000 = 500$$\left( \text{Since } E_{NaOH} = 40 \right)$

Class 11 Chemistry Some Basic Concepts of Chemistry Atomic, Molecular and Equivalent masses

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Calculate the milli-equivalents of:
$(a) \, Ca(OH)_2$ in $74 \, g$
$(b) \, NaOH$ in $20 \, g$ respectively.

A
$2000, 500$
B
$500, 2000$
C
$50, 200$
D
$200, 50$

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Some Basic Concepts of Chemistry

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Atomic, Molecular and Equivalent masses

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In terms of energy,$1 \ amu$ is equal to:

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Sulfur reacts with chlorine to form $S_2Cl_2$ and $SCl_2$. The equivalent mass of sulfur in $SCl_2$ is ................. $g/mol$.

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Calculate the milli-equivalents of:$(a) \, Ca(OH)_2$ in $74 \, g$$(b) \, NaOH$ in $20 \, g$ respectively.

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$1.520 \ g$ of the hydroxide of a metal on ignition gave $0.995 \ g$ of oxide. The equivalent weight of the metal is:

At $STP$,if $5.6 \ L$ of a gas weighs $7.5 \ g$,then identify the gas.

The vapor density of a metal chloride is $77$. If the equivalent weight of the metal is $3$,what is its atomic weight?

In terms of energy,$1 \ amu$ is equal to:

Sulfur reacts with chlorine to form $S_2Cl_2$ and $SCl_2$. The equivalent mass of sulfur in $SCl_2$ is ................. $g/mol$.

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Calculate the milli-equivalents of:
$(a) \, Ca(OH)_2$ in $74 \, g$
$(b) \, NaOH$ in $20 \, g$ respectively.