In chlorine gas,the ratio of Cl^{35} and Cl^{ | vedclass

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(B) The average atomic mass of chlorine is $35.5 \ u$. Let the percentage abundance of $Cl^{37}$ be $x$ and $Cl^{35}$ be $(100 - x)$. Using the formul

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$3:1$

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(B) The average atomic mass of chlorine is $35.5 \ u$. Let the percentage abundance of $Cl^{37}$ be $x$ and $Cl^{35}$ be $(100 - x)$. Using the formula: $	ext{Average Atomic Mass} = \frac{x 	imes 37 + (100 - x) 	imes 35}{100}$. $35.5 = \frac{37x + 3500 - 35x}{100}$. $3550 = 2x + 3500$. $2x = 50$,so $x = 25$. Thus,the abundance of $Cl^{37}$ is $25\%$ and $Cl^{35}$ is $75\%$. The ratio of $Cl^{35} : Cl^{37}$ is $75 : 25$,which simplifies to $3 : 1$.

In chlorine gas,the ratio of $Cl^{35}$ and $Cl^{37}$ is

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