$10 \, g$ of $CaCO_3$ contains
- A$10 \, \text{moles}$ of $CaCO_3$
- B$0.1 \, \text{g-atom}$ of $Ca$
- C$6 \times 10^{23} \, \text{atoms}$ of $Ca$
- D$0.1 \, \text{equivalent}$ of $Ca$
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