In Convent Model School,60 % of the students | vedclass

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Question

(NONE) Let the total number of students be $y$.
Number of boys $= 60\% 	ext{ of } y = 0.6y = \frac{3y}{5}$.
Number of girls $= 40\% 	ext{ of } y =

Vedclass · Accepted Answer

$\frac{8}{15}$

Vedclass · Answer

(NONE) Let the total number of students be $y$.
Number of boys $= 60\% 	ext{ of } y = 0.6y = \frac{3y}{5}$.
Number of girls $= 40\% 	ext{ of } y = 0.4y = \frac{2y}{5}$.
Number of girls scoring more than $40$ marks $= 80\% 	ext{ of } \frac{2y}{5} = 0.8 	imes 0.4y = 0.32y = \frac{8y}{25}$.
Total students scoring more than $40$ marks $= 60\% 	ext{ of } y = 0.6y = \frac{3y}{5}$.
Number of boys scoring more than $40$ marks $=$ (Total students scoring $> 40$) $-$ (Girls scoring $> 40$)
$= 0.6y - 0.32y = 0.28y = \frac{7y}{25}$.
Number of boys scoring $40$ marks or less $=$ (Total boys) $-$ (Boys scoring $> 40$)
$= 0.6y - 0.28y = 0.32y = \frac{8y}{25}$.
Fraction of boys scoring $40$ marks or less $= \frac{	ext{Boys scoring } \le 40}{	ext{Total boys}} = \frac{0.32y}{0.6y} = \frac{32}{60} = \frac{8}{15}$.

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