In the figure,two blocks M and m are tied tog | vedclass

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(D) When the elevator accelerates downward with acceleration $a_0$,a pseudo force $ma_0$ acts upward on both blocks in the frame of the elevator.For b

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All of the above

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(D) When the elevator accelerates downward with acceleration $a_0$,a pseudo force $ma_0$ acts upward on both blocks in the frame of the elevator.For block $M$: The normal force $N$ is given by $N = M(g - a_0)$. The limiting friction force is $f_L = \mu N = \mu M(g - a_0)$. Since $(g - a_0) For block $m$: The effective weight is $m(g - a_0)$. The tension $T$ in the string is reduced because the effective gravitational pull is reduced. Thus,option $(B)$ is correct.For the system to accelerate,the driving force must exceed the limiting friction. The driving force is the effective weight of $m$,which is $m(g - a_0)$. The limiting friction is $\mu M(g - a_0)$. The system will accelerate if $m(g - a_0) > \mu M(g - a_0)$,which simplifies to $m > \mu M$. Thus,option $(C)$ is correct.Since all statements are correct,the correct option is $(D)$.

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