In Fresnel's biprism experiment,on increasing | vedclass

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(B) The fringe width $\beta$ in a Fresnel's biprism experiment is given by the formula $\beta = \frac{\lambda D}{d}$,where $\lambda$ is the wavelength

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Decrease

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(B) The fringe width $\beta$ in a Fresnel's biprism experiment is given by the formula $\beta = \frac{\lambda D}{d}$,where $\lambda$ is the wavelength of light,$D$ is the distance between the source and the screen,and $d$ is the distance between the two virtual sources.In a biprism,the distance between the two virtual sources is given by $d = 2a(\mu - 1)\alpha$,where $a$ is the distance of the source from the biprism,$\mu$ is the refractive index of the prism material,and $\alpha$ is the refracting angle of the prism.Substituting $d$ in the fringe width formula,we get $\beta = \frac{\lambda D}{2a(\mu - 1)\alpha}$.From this relation,it is clear that $\beta \propto \frac{1}{\alpha}$.Therefore,on increasing the prism angle $\alpha$,the fringe width $\beta$ will decrease.

In Fresnel's biprism experiment,on increasing the prism angle,the fringe width will

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