In Freundlich adsorption,the amount of gas adsorbed is proportional to pressure $P$ as

If the value of $\frac{1}{n}$ is equal to $1$ in the Freundlich adsorption isotherm, then $\frac{x}{m} = $ (where $x = $ mass of adsorbate, $m = $ mass of the adsorbent, $p = $ pressure of the gas).

What kind of difference is observed in the amount of adsorption with the increase in temperature?

Physical adsorption is inversely proportional to the

When the temperature is lowered and pressure is raised,the adsorption of a gas on a solid

Select the graph that correctly describes the adsorption isotherms at two temperatures $T_{1}$ and $T_{2}$ $\left(T_{1}>T_{2}\right)$ for a gas :
($x-$ mass of the gas adsorbed ; $m-$ mass of adsorbent ; $P -$ pressure)