If the value of frac{1}{n} is equal to 1 in t | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The Freundlich adsorption isotherm is given by the equation: $\frac{x}{m} = K p^{\frac{1}{n}}$.Here, $\frac{x}{m}$ represents the mass of adsorbat

Vedclass · Accepted Answer

$K p$

Vedclass · Answer

(B) The Freundlich adsorption isotherm is given by the equation: $\frac{x}{m} = K p^{\frac{1}{n}}$.Here, $\frac{x}{m}$ represents the mass of adsorbate per unit mass of adsorbent, $p$ is the pressure, and $K$ and $n$ are constants depending on the nature of the adsorbent and adsorbate at a particular temperature.Given that the value of $\frac{1}{n} = 1$.Substituting this value into the equation, we get: $\frac{x}{m} = K p^{1} = K p$.Therefore, the correct option is $B$.

If the value of $\frac{1}{n}$ is equal to $1$ in the Freundlich adsorption isotherm, then $\frac{x}{m} = $ (where $x = $ mass of adsorbate, $m = $ mass of the adsorbent, $p = $ pressure of the gas).

Similar Questions

Adsorption is accompanied by

What is the value of the slope in the Freundlich adsorption isotherm plot of $\log \frac{x}{m}$ against $\log C$?

Select the correct statement.

In Freundlich adsorption,the amount of gas adsorbed is proportional to pressure $P$ as

Adsorption is multilayer in the case of

Vedclass Test Series

Exam Paper Generator

Online Exam Module