(C) The power rating of a bulb is given by the formula $P = \frac{V^2}{R}$,where $V$ is the voltage and $R$ is the resistance.For the bulb used in Ind

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(C) The power rating of a bulb is given by the formula $P = \frac{V^2}{R}$,where $V$ is the voltage and $R$ is the resistance.For the bulb used in India: $R = \frac{V_{India}^2}{P} = \frac{(220)^2}{60}$.For the bulb used in the $USA$: $R' = \frac{V_{USA}^2}{P} = \frac{(110)^2}{60}$.Dividing the two equations: $\frac{R}{R'} = \frac{(220)^2}{(110)^2} = \left(\frac{220}{110}\right)^2 = 2^2 = 4$.Therefore,$R' = \frac{R}{4}$.

Class 11 Chemistry Data Entry - Chemistry Level 0 of all question bank

In India,electricity is supplied for domestic use at $220 \,V$. It is supplied at $110 \,V$ in the $USA$. If the resistance of a $60 \,W$ bulb for use in India is $R$,what will be the resistance of a $60 \,W$ bulb for use in the $USA$?

AIPMT 2004 All AIPMT

A
$R$
B
$2 R$
C
$\frac{R}{4}$
D
$\frac{R}{2}$

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In India,electricity is supplied for domestic use at $220 \,V$. It is supplied at $110 \,V$ in the $USA$. If the resistance of a $60 \,W$ bulb for use in India is $R$,what will be the resistance of a $60 \,W$ bulb for use in the $USA$?

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