In the nitration of benzene,concentrated HNO_ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) In the nitration of benzene,the reaction between concentrated $HNO_3$ and concentrated $H_2SO_4$ occurs as follows:$HNO_3 + H_2SO_4 \rightleftharp

Vedclass · Accepted Answer

Bronsted base

Vedclass · Answer

(A) In the nitration of benzene,the reaction between concentrated $HNO_3$ and concentrated $H_2SO_4$ occurs as follows:$HNO_3 + H_2SO_4 \rightleftharpoons H_2NO_3^+ + HSO_4^-$$H_2NO_3^+ \rightleftharpoons H_2O + NO_2^+$Here,$HNO_3$ accepts a proton $(H^+)$ from $H_2SO_4$ to form $H_2NO_3^+$. According to the Bronsted-Lowry theory,a substance that accepts a proton acts as a Bronsted base.

In the nitration of benzene,concentrated $HNO_3$ acts as a:

Similar Questions

In the given reaction,$C_6H_6 + HNO_3 \xrightarrow{H_2SO_4} C_6H_5NO_2 + H_2O$,$HNO_3$ acts as:

What is the molecular formula of the product formed when benzene is reacted with ethyl chloride in the presence of anhydrous aluminium chloride?

Amongst the following compounds,the one which is most easily sulphonated is:

The major product obtained in the given reaction is:

$C_6H_6 + CH_3Cl \xrightarrow{anhydrous \ AlCl_3} C_6H_5CH_3 + HCl$ is an example of

Vedclass Test Series

Exam Paper Generator

Online Exam Module