In Ohm's experiment,the values of an unknown | vedclass

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(A) Step $1$: Calculate the mean value of resistance $\bar{R}$.$\bar{R} = \frac{4.12 + 4.08 + 4.22 + 4.14}{4} = \frac{16.56}{4} = 4.14 \; \Omega$.Step

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$0.04, 0.0096$

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(A) Step $1$: Calculate the mean value of resistance $\bar{R}$.$\bar{R} = \frac{4.12 + 4.08 + 4.22 + 4.14}{4} = \frac{16.56}{4} = 4.14 \; \Omega$.Step $2$: Calculate the absolute errors in each measurement.$\Delta R_1 = |4.14 - 4.12| = 0.02 \; \Omega$$\Delta R_2 = |4.14 - 4.08| = 0.06 \; \Omega$$\Delta R_3 = |4.14 - 4.22| = 0.08 \; \Omega$$\Delta R_4 = |4.14 - 4.14| = 0.00 \; \Omega$Step $3$: Calculate the mean absolute error $\Delta \bar{R}$.$\Delta \bar{R} = \frac{0.02 + 0.06 + 0.08 + 0.00}{4} = \frac{0.16}{4} = 0.04 \; \Omega$.Step $4$: Calculate the relative error.Relative error $= \frac{\Delta \bar{R}}{\bar{R}} = \frac{0.04}{4.14} \approx 0.00966 \approx 0.0096$.

In Ohm's experiment,the values of an unknown resistance were found to be $4.12 \; \Omega, 4.08 \; \Omega, 4.22 \; \Omega$,and $4.14 \; \Omega$. Calculate the mean absolute error and relative error in these measurements.

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