(B) In Lassaigne's test,the organic compound is fused with metallic sodium. If the compound contains nitrogen,it reacts with sodium to form sodium cya

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(B) In Lassaigne's test,the organic compound is fused with metallic sodium. If the compound contains nitrogen,it reacts with sodium to form sodium cyanide $(NaCN)$.The chemical reaction is: $C + N + Na \rightarrow NaCN$.This $NaCN$ is then extracted with water and tested for the presence of cyanide ions.

Class 11 Chemistry 8-3.Organic Chemistry : Purification and characterization Chemical analysis of organic compounds

Medium

In organic compounds,nitrogen is tested in Lassaigne's test as:

A
$NaNH_2$
B
$NaCN$
C
$NaNO_2$
D
$NaNO_3$

Explore More

Browse All

Question Bank

All Subjects

Class 11 Questions

Class 11

Chemistry Questions

Chapter

8-3.Organic Chemistry : Purification and characterization

Subtopic

Chemical analysis of organic compounds

In the Lassaigne sodium fusion test,$N$ and $S$ of an organic compound are converted into:

MediumAP EAMCET 2021

View Solution

Match the compounds in Column $I$ with their characteristic test$(s)$ reaction$(s)$ given in Column $II$.

Column $I$ Column $II$

$A. H_2N-NH_3^+Cl^-$ $p. \text{Sodium fusion extract of the compound gives Prussian blue colour with } FeSO_4$

$B. HO-C_6H_4-CH(NH_3^+)COOH \text{ (with } I^- \text{ counterion)}$ $q. \text{Gives positive } FeCl_3 \text{ test}$

$C. HO-C_6H_4-NH_3^+Cl^-$ $r. \text{Gives white precipitate with } AgNO_3$

$D. (NO_2)_2C_6H_3-NH-NH_3^+Br^-$ $s. \text{Reacts with aldehydes to form the corresponding hydrazone derivative}$

Column $I$	Column $II$
$A. H_2N-NH_3^+Cl^-$	$p. \text{Sodium fusion extract of the compound gives Prussian blue colour with } FeSO_4$
$B. HO-C_6H_4-CH(NH_3^+)COOH \text{ (with } I^- \text{ counterion)}$	$q. \text{Gives positive } FeCl_3 \text{ test}$
$C. HO-C_6H_4-NH_3^+Cl^-$	$r. \text{Gives white precipitate with } AgNO_3$
$D. (NO_2)_2C_6H_3-NH-NH_3^+Br^-$	$s. \text{Reacts with aldehydes to form the corresponding hydrazone derivative}$