In the presence of $NaOH$,phenol reacts with $CHCl_3$ to form $o$-hydroxybenzaldehyde. This reaction is called:
- AReimer-Tiemann reaction
- BSandmeyer's reaction
- CHoffmann's degradation reaction
- DGattermann's aldehyde synthesis
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Similar Questions
The major product in the following reaction is:
Identify $(C)$ in the reaction$(s)$:
$p\text{-toluidine}$ $\xrightarrow[{0\,^{\circ}C}]{{NaNO_2/HCl}}\,(A)\,$ $\xrightarrow{{{H_2}O, \Delta }}\,(B)\,$ $\xrightarrow[{(ii)\,dil.\,HCl}]{{(i)\,CHCl_3, KOH, \Delta }}\,(C)$
$p\text{-toluidine}$ $\xrightarrow[{0\,^{\circ}C}]{{NaNO_2/HCl}}\,(A)\,$ $\xrightarrow{{{H_2}O, \Delta }}\,(B)\,$ $\xrightarrow[{(ii)\,dil.\,HCl}]{{(i)\,CHCl_3, KOH, \Delta }}\,(C)$
Difficult
View SolutionWhich of the following compounds has the least $pK_a$ value?
Medium
View Solution$I$. $1,2$-dihydroxybenzene
$II$. $1,3$-dihydroxybenzene
$III$. $1,4$-dihydroxybenzene
$IV$. Hydroxybenzene
The increasing order of boiling points of the above-mentioned compounds is:
$II$. $1,3$-dihydroxybenzene
$III$. $1,4$-dihydroxybenzene
$IV$. Hydroxybenzene
The increasing order of boiling points of the above-mentioned compounds is:
Which of the following substances does not contain a $-COOH$ group?
Medium
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