In the Rutherford scattering experiment,what | vedclass

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(D) The impact parameter $b$ is related to the scattering angle $	heta$ by the formula: $b = \frac{1}{4\pi\epsilon_0} \cdot \frac{Ze^2 \cot(	heta/2)

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$180$

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(D) The impact parameter $b$ is related to the scattering angle $	heta$ by the formula: $b = \frac{1}{4\pi\epsilon_0} \cdot \frac{Ze^2 \cot(	heta/2)}{K}$,where $K$ is the kinetic energy of the $\alpha$-particle.Given that $b = 0$,we have $\cot(	heta/2) = 0$.This implies $	heta/2 = 90^o$,which gives $	heta = 180^o$.Therefore,for an impact parameter of $0$,the $\alpha$-particle retraces its path,resulting in a scattering angle of $180^o$.

In the Rutherford scattering experiment,what will be the correct scattering angle $\theta$ for an $\alpha$-particle with an impact parameter $b = 0$ (in $^o$)?

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