In sea urchin DNA,which is double stranded,17 | vedclass

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(A) According to Chargaff's rule,for double-stranded $DNA$,the amount of adenine $(A)$ is equal to thymine $(T)$,and the amount of guanine $(G)$ is eq

Vedclass · Accepted Answer

$G\ 17\%, A\ 33\%, T\ 33\%$

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(A) According to Chargaff's rule,for double-stranded $DNA$,the amount of adenine $(A)$ is equal to thymine $(T)$,and the amount of guanine $(G)$ is equal to cytosine $(C)$,i.e.,$A = T$ and $G = C$.Given that cytosine $(C)$ is $17\%$,therefore,guanine $(G)$ must also be $17\%$.The total percentage of all four bases is $100\%$.So,$A + T + G + C = 100\%$.Substituting the known values: $A + T + 17\% + 17\% = 100\%$.$A + T + 34\% = 100\%$.$A + T = 100\% - 34\% = 66\%$.Since $A = T$,the percentage of adenine $(A)$ is $66\% / 2 = 33\%$ and the percentage of thymine $(T)$ is $66\% / 2 = 33\%$.Thus,the percentages are $G = 17\%, A = 33\%, T = 33\%$.

In sea urchin $DNA$,which is double stranded,$17\%$ of the bases were shown to be cytosine. The percentages of the other three bases expected to be present in this $DNA$ are

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