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(C) In a series $LCR$ circuit,the impedance is given by $Z = \sqrt{R^2 + (X_L - X_C)^2}$ and the phase angle $\phi$ is given by $	an \phi = \frac{X_L

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$\omega > \omega_0$

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(C) In a series $LCR$ circuit,the impedance is given by $Z = \sqrt{R^2 + (X_L - X_C)^2}$ and the phase angle $\phi$ is given by $	an \phi = \frac{X_L - X_C}{R}$.Voltage leads the current when the phase angle $\phi$ is positive,which implies $X_L > X_C$.Substituting the expressions for inductive reactance $(X_L = \omega L)$ and capacitive reactance $(X_C = \frac{1}{\omega C})$,we get $\omega L > \frac{1}{\omega C}$.This simplifies to $\omega^2 > \frac{1}{LC}$.Since the resonant angular frequency is $\omega_0 = \frac{1}{\sqrt{LC}}$,we have $\omega_0^2 = \frac{1}{LC}$.Therefore,the condition for voltage to lead the current is $\omega^2 > \omega_0^2$,which implies $\omega > \omega_0$.

In a series $LCR$ circuit,the voltage leads the current when (Given that $\omega_0$ is the resonant angular frequency):

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