(B) Using De Morgan's Law,$\overline {\bar A \cdot \bar B} = \overline{\bar A} + \overline{\bar B} = A + B$. Substituting this into the expression: $(

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(B) Using De Morgan's Law,$\overline {\bar A \cdot \bar B} = \overline{\bar A} + \overline{\bar B} = A + B$. Substituting this into the expression: $(A + B) \cdot A$. Expanding the expression: $A \cdot A + B \cdot A$. Since $A \cdot A = A$,we get $A + AB$. Factoring out $A$: $A(1 + B)$. Since $(1 + B) = 1$,the expression simplifies to $A \cdot 1 = A$.