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(B) The centre of mass of a system of two particles is defined by the position vector $\vec{R}_{cm} = \frac{m_1\vec{r}_1 + m_2\vec{r}_2}{m_1 + m_2}$.S

Vedclass · Accepted Answer

on the line joining the two particles.

Vedclass · Answer

(B) The centre of mass of a system of two particles is defined by the position vector $\vec{R}_{cm} = \frac{m_1\vec{r}_1 + m_2\vec{r}_2}{m_1 + m_2}$.Since the position vector of the centre of mass is a weighted average of the position vectors of the two particles,it must lie on the line segment connecting the two particles.If the masses are equal $(m_1 = m_2)$,the centre of mass lies exactly at the midpoint.If the masses are different,it lies closer to the heavier mass,but it always remains on the line joining the two particles.Therefore,option $B$ is correct.

In the case of a system of two particles of different masses,the centre of mass lies

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