In the circuit shown, inputs $A$ and $B$ are in states $1$ and $0$ respectively. What is the only possible stable state of the outputs $X$ and $Y$?
- A$X=1, Y=1$
- B$X=1, Y=0$
- C$X=0, Y=1$
- D$X=0, Y=0$
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Similar Questions
$A$ truth table is given below. Which of the following logic gates corresponds to this truth table?
$A: 0, 1, 0, 1$
$B: 0, 0, 1, 1$
$Y: 1, 0, 0, 0$
$A: 0, 1, 0, 1$
$B: 0, 0, 1, 1$
$Y: 1, 0, 0, 0$
Which of the following Boolean equations is incorrect?
Medium
View SolutionWhat will be the outputs $Y$ for the inputs $(A = 1, B = 0)$,$(A = 1, B = 1)$,and $(A = 0, B = 0)$ respectively?
Difficult
View SolutionThe circuit diagram shows a combination of logic gates. When inputs $P$ and $Q$ change to state $0$ with inputs $R$ and $S$ still at state $1$,the states of outputs $X$,$Y$ and $Z$ change to:
Difficult
View SolutionFor the given logic circuit,to have the output $Y=1$,the possible combinations of inputs are:
$a) A=0, B=1$
$b) A=1, B=0$
$c) A=0, B=0$
$d) A=1, B=1$
$a) A=0, B=1$
$b) A=1, B=0$
$c) A=0, B=0$
$d) A=1, B=1$
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