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(B) Since the resistors are connected in parallel,the potential difference $V$ across both resistors is the same.The power dissipated in a resistor is

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$9$

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(B) Since the resistors are connected in parallel,the potential difference $V$ across both resistors is the same.The power dissipated in a resistor is given by the formula $P = \frac{V^2}{R}$.For the $6 \, \Omega$ resistor,$P_1 = 6 \, W$ and $R_1 = 6 \, \Omega$. Thus,$6 = \frac{V^2}{6}$,which implies $V^2 = 36$.For the $4 \, \Omega$ resistor,$P_2 = \frac{V^2}{R_2} = \frac{36}{4} = 9 \, W$.Alternatively,since $V$ is constant,$P \propto \frac{1}{R}$,so $\frac{P_1}{P_2} = \frac{R_2}{R_1}$.Substituting the values: $\frac{6}{P_2} = \frac{4}{6} = \frac{2}{3}$.Therefore,$P_2 = 6 	imes \frac{3}{2} = 9 \, W$.

In the circuit shown below,the power developed in the $6 \, \Omega$ resistor is $6 \, W$. The power in watts developed in the $4 \, \Omega$ resistor is

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