In the circuit shown in the figure,the current gain $\beta = 100$ for an $npn$ transistor. What should be the base resistor $R_B$ so that $V_{CE} = 5 \text{ V}$,given $V_{BE} = 0 \text{ V}$?

An $n-p-n$ transistor power amplifier in $C-E$ configuration gives

In the common emitter configuration of a transistor,the current gain is more than $1$. Given that $I_{b}$,$I_{e}$,and $I_{c}$ are the base,emitter,and collector currents respectively,which of the following relations is correct?

The current gain for a transistor working as a common base amplifier is $0.96$. If the emitter current is $7.2 \,mA$, then the base current is (in $\,mA$)

$A$ transistor is connected in a common base circuit with $\beta = 75$. For an emitter current of $5 \text{ mA}$,the value of the collector current is ........ $\text{mA}$.

An $N-P-N$ transistor in a common emitter mode is used as a simple voltage amplifier with a collector current of $4 \ mA$. The terminal of an $8 \ V$ battery is connected to the collector through a load resistance $R_L$ and to the base through a resistance $R_B$. The collector-emitter voltage $V_{CE} = 4 \ V$,base-emitter voltage $V_{BE} = 0.6 \ V$ and base current amplification factor $\beta_{d.c.} = 100$. Calculate the values of $R_L$ and $R_B$.