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(D) Given: $\beta = 75$,$I_e = 5 	ext{ mA}$.We know the relationship between current gain $\beta$ and $\alpha$ is given by $\beta = \frac{\alpha}{1 -

Vedclass · Accepted Answer

$4.93$

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(D) Given: $\beta = 75$,$I_e = 5 	ext{ mA}$.We know the relationship between current gain $\beta$ and $\alpha$ is given by $\beta = \frac{\alpha}{1 - \alpha}$.Substituting the value of $\beta$: $75 = \frac{\alpha}{1 - \alpha} \implies 75(1 - \alpha) = \alpha \implies 75 - 75\alpha = \alpha$.Solving for $\alpha$: $76\alpha = 75 \implies \alpha = \frac{75}{76}$.Since $\alpha = \frac{I_c}{I_e}$,the collector current $I_c$ is given by $I_c = \alpha I_e$.Substituting the values: $I_c = \left(\frac{75}{76}ight) 	imes 5 	ext{ mA} \approx 4.93 	ext{ mA}$.

$A$ transistor is connected in a common base circuit with $\beta = 75$. For an emitter current of $5 \text{ mA}$,the value of the collector current is ........ $\text{mA}$.

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