In the complex K_2Fe[Fe(CN)_6],which of the f | vedclass

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(A) The complex $K_2Fe[Fe(CN)_6]$ is also known as Prussian blue or Turnbull's blue depending on the synthesis,but here we analyze the oxidation state

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both $Fe$ atoms are in the same oxidation state

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(A) The complex $K_2Fe[Fe(CN)_6]$ is also known as Prussian blue or Turnbull's blue depending on the synthesis,but here we analyze the oxidation states.Let the oxidation state of $Fe$ be $x$.$2(+1) + x + [x + 6(-1)] = 0$$2 + x + x - 6 = 0$$2x = 4$$x = +2$Both iron atoms are in the $+2$ oxidation state.The coordination number of the central $Fe$ atom in the $[Fe(CN)_6]^{4-}$ ion is $6$ because it is surrounded by $6$ $CN^-$ ligands.$CN^-$ is a strong field ligand,so the complex is a low spin complex.

In the complex $K_2Fe[Fe(CN)_6]$,which of the following statements is correct?

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