In the cyclotron, as the radius of the circul | vedclass

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(B) In a cyclotron, a charged particle moves in a circular path under the influence of a perpendicular magnetic field $B$. The magnetic force provides

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$V$ increases, $\omega$ remains constant.

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(B) In a cyclotron, a charged particle moves in a circular path under the influence of a perpendicular magnetic field $B$. The magnetic force provides the necessary centripetal force: $qvB = \frac{mv^2}{r}$.From this, the linear velocity is $V = \frac{qBr}{m}$. As the radius $r$ increases, the linear velocity $V$ increases.The angular velocity $\omega$ is given by $\omega = \frac{V}{r} = \frac{qB}{m}$.Since $q$, $B$, and $m$ are constants for a given particle in a cyclotron, the angular velocity $\omega$ remains constant regardless of the radius $r$.

In the cyclotron, as the radius of the circular path of the charged particle increases, ($\omega$ = angular velocity, $V$ = linear velocity)

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